Maths on a Mug #16
#mathsonamug pic.twitter.com/Rd0IAC9YHw — Sean Elvidge (@seanelvidge) November 17, 2016 Perhaps a “simple” #mathsonthemug this time. Simple, but very important. This is Bayes’ theorem: \[P(A|B) = \frac{P(B|A)P(A)}{P(B)}.\] This relates the probability of observing \(A\) given that \(B\) is true where \(A\) and \(B\) are events, we also require that the probability of \(B\) does not equal […]